The canonical kernel word of a displayed hook arrow #
The negative tail after a positive hook boundary is independent of the word before that boundary. More precisely, its positive reversal is determined by the displayed central arrow. The proof splits a nonempty tail at the arrow adjacent to the center: the degree-two condition determines that arrow, and special-biserial continuation uniqueness determines the remaining path at each fixed length. Replaying a hook onto the trivial source word shows that maximal tails have the same length.
The first arrow adjacent to the base of a nonempty negative extension, together with the path before it.
- vertex : Q
- path_eq : arm.ordinaryPath = self.initialPath.comp self.arrow.toPath
- initialPath_length : self.initialPath.length + 1 = arm.steps
- first_valid : IsString R (Quiver.Path.comp C.path (Quiver.Hom.toPath (negativeArrow self.arrow)))
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Extract the boundary-adjacent arrow of a nonempty negative extension.
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Read the ordinary path of a negative extension as a positive string word.
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Two equal-length negative tails after the same displayed positive arrow have the same positive word, even when the preceding base word differs. It is enough here to compare an arbitrary base with the trivial base used for the canonical hook.
A canonical maximal hook based at the trivial word of a displayed arrow's source.
- hook : (Word.vertex P.relations ⋯ a.snd.fst).HookExtension self.result
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Choose the canonical-base maximal hook belonging to a displayed arrow.
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The positive tail word canonically determined by a displayed arrow.
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The tail word of any maximal hook is the canonical word of its displayed boundary arrow.
Transporting the source word of a hook does not alter its displayed arrow.