Endpoint subbimodules form chains #
Lemma 3.1(3) (lem:endpoint-chains, projective-rays.tex). For a
representation-finite algebra A over an algebraically closed field with
primitive idempotents e_x, put R_x = e_xAe_x.
- Each
R_xis local with residue fieldk:R_x = k e_x + rad R_x, withrad R_x = R_x ∩ rad Anilpotent. - An
R_x--R_y-subbimoduleNofA(x, y)is recovered from the ideal it generates,e_x(ANA)e_y = N; so there are finitely many. - Two incomparable subbimodules would give
k²in the socle of(N₁ + N₂)/(N₁ ∩ N₂), whose infinitely many lines lift to distinct subbimodules; so the subbimodules form a chain, with one-dimensional successive quotients. - For
f ≠ 0,R_xfR_y = R_xforfR_y.
Jacobson's lemma.
An element x with 1 - yx invertible for all y lies in the Jacobson
radical.
R_x = k e_x + rad R_x.
The radical of a finite-dimensional algebra is nilpotent.
The two-sided ideal generated by a subspace: the span of all a n b.
Instances For
Finitely many endpoint subbimodules: each is recovered from the ideal it generates.
Nakayama's lemma for subbimodules. If P ≤ (rad R_x) P + P (rad R_y) + L
for a subbimodule L, then P ≤ L.
(rad R_x) N + N (rad R_y) is a subbimodule.
Subspaces between N' and N, where N/N' is killed by the radicals, are
subbimodules.
A subbimodule properly above L ≤ N inside N has a minimal member P
with (rad R_x) P + P (rad R_y) ≤ L.
Lemma 3.1(3): the endpoint subbimodules form a chain.
Consecutive endpoint subbimodules have one-dimensional quotient.
Lemma 3.1(3), last part: R_x f R_y = R_x f or f R_y.